(x^2-x-2)/(x^2-4x+3)=0

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Solution for (x^2-x-2)/(x^2-4x+3)=0 equation:


D( x )

x^2-(4*x)+3 = 0

x^2-(4*x)+3 = 0

x^2-(4*x)+3 = 0

x^2-4*x+3 = 0

x^2-4*x+3 = 0

DELTA = (-4)^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+4)/(1*2) or x = (4-4^(1/2))/(1*2)

x = 3 or x = 1

x in (-oo:1) U (1:3) U (3:+oo)

(x^2-x-2)/(x^2-(4*x)+3) = 0

(x^2-x-2)/(x^2-4*x+3) = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

(x+1)*(x-2) = 0

x^2-4*x+3 = 0

x^2-4*x+3 = 0

DELTA = (-4)^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+4)/(1*2) or x = (4-4^(1/2))/(1*2)

x = 3 or x = 1

(x-1)*(x-3) = 0

((x+1)*(x-2))/((x-1)*(x-3)) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -1, 2 }

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